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0=5x^2+9x-99
We move all terms to the left:
0-(5x^2+9x-99)=0
We add all the numbers together, and all the variables
-(5x^2+9x-99)=0
We get rid of parentheses
-5x^2-9x+99=0
a = -5; b = -9; c = +99;
Δ = b2-4ac
Δ = -92-4·(-5)·99
Δ = 2061
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2061}=\sqrt{9*229}=\sqrt{9}*\sqrt{229}=3\sqrt{229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{229}}{2*-5}=\frac{9-3\sqrt{229}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{229}}{2*-5}=\frac{9+3\sqrt{229}}{-10} $
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